Q:

On rainy days, Izzy goes from his house to the school by running 1.2 miles on West St, then makes a 90º turn and runs 0.5 miles on North Ave.a. If Izzy runs 7.5 miles per hour, approximately how much time will it take her to run to school on rainy days?b. On dry days, Izzy runs on the dashed path through the woods. How far is she traveling?c. If Izzy runs 7.5 miles per hour, how much time will she save by cutting through the woods?

Accepted Solution

A:
Answer:a) It will take Izzy 0.226 hours = 13.6 minutes = 13 minutes 36 seconds to run to school on dashed days.b) Izzy runs 1.30 miles on dry days.c) Izzy saves 3 minutes and 12 seconds cutting through the woods.Step-by-step explanation:This problem can be solved by a simpe rule of three problem.a) On rainy days, she runs 1.2 + 0.5 = 1.7 miles.The problem states that for rainy days, she runs 7.5 miles per hour. We know that in a hour, Izzy will run 7.5 miles. We want to know how long it takes for her to run 1.7 miles. So1 hour - 7.5 milesx hours - 1.7 miles7.5x = 1.7[tex]x = \frac{1.7}{7.5}[/tex]x = 0.226 hoursIt will take Izzy 0.226 hours = 13.6 minutes = 13 minutes 36 seconds to run to school on dashed days.b) Now we have a right triangle, where the sides are the 1.2 miles and the 0.5miles, and the path through the woods x is the hypotenuse.So, we apply the pythagorean theorem.[tex]x^{2} = (1.2)^{2} + (0.5)^{2}[/tex][tex]x^{2} = 1.44 + 0.25[/tex][tex]x^{2} = 1.69[/tex][tex]x = 1.30[/tex]So, Izzy runs 1.30 miles on dry days.c) The first step for this question is knowing how long it takes for Izzy to run 1.30 miles at 7.50 miles a hour. So:1 hour - 7.50 milesx hours = 1.30 miles7.50x = 1.30[tex]x = \frac{1.3}{7.5}[/tex]x = 0.173 hoursSo, it takes Izzy 0.173 hours = 10.4 minutes = 10 minutes 24 seconds to run through the woods. 13' 36''-10' 24'' 3' 12''Izzy saves 3 minutes and 12 seconds cutting through the woods.